ZHCSPF2A December 2021 – September 2022 LM5168 , LM5169
PRODUCTION DATA
The primary output capacitor, COUT1, can be selected using either Equation 14 or Equation 15. For this design, an output voltage ripple of 5 mV and a load transient of 0.2 V is used. From this, a ripple current of 0.34 A at 60-V input, and a peak transformer current of 0.77 A at full load is calculated. The two output capacitor equations give values of 11 μF and 5 μF. Because of the large derating of ceramic capacitors, COUT1 = 1 × 22 μF is used. Keep in mind that the equations give the minimum capacitance value and in no case should the capacitance of COUT1 be less than 2.2 μF. More output capacitance can be used to improve load transient response. Also note that when using type 3 ripple injection, the actual ripple voltage appearing on the output can be kept small.
where
where
COUT2 is selected using Equation 16. In this case, a ripple voltage on the secondary otuput of 20 mV is chosen. The minimum input voltage must be used in this equation. A value of 10 μF is calculated and 1 × 22 μF for COUT2 is selected. Again, the equation gives the minimum capacitance value and in no case should the capacitance of COUT2 be less than 2.2 μF.
Both output capacitors should be X7R ceramics in a 1206 or 1210 case size, and rated for at least twice the output voltage.