ZHCSMO4N February   1977  – June 2024 TL081 , TL081A , TL081B , TL081H , TL082 , TL082A , TL082B , TL082H , TL084 , TL084A , TL084B , TL084H

PRODUCTION DATA  

  1.   1
  2. 特性
  3. 应用
  4. 说明
  5. Pin Configuration and Functions
  6. Specifications
    1. 5.1  Absolute Maximum Ratings
    2. 5.2  ESD Ratings
    3. 5.3  Recommended Operating Conditions
    4. 5.4  Thermal Information for Single Channel
    5. 5.5  Thermal Information for Dual Channel
    6. 5.6  Thermal Information for Quad Channel
    7. 5.7  Electrical Characteristics: TL08xH
    8. 5.8  Electrical Characteristics (DC): TL08xC, TL08xAC, TL08xBC, TL08xI, TL08xM
    9. 5.9  Electrical Characteristics (AC): TL08xC, TL08xAC, TL08xBC, TL08xI, TL08xM
    10. 5.10 Typical Characteristics: TL08xH
  7. Parameter Measurement Information
  8. Detailed Description
    1. 7.1 Overview
    2. 7.2 Functional Block Diagram
    3. 7.3 Feature Description
      1. 7.3.1 Total Harmonic Distortion
      2. 7.3.2 Slew Rate
    4. 7.4 Device Functional Modes
  9. Applications and Implementation
    1. 8.1 Application Information
    2. 8.2 Typical Applications
      1. 8.2.1 Inverting Amplifier Application
        1. 8.2.1.1 Design Requirements
        2. 8.2.1.2 Detailed Design Procedure
        3. 8.2.1.3 Application Curve
    3. 8.3 System Examples
      1. 8.3.1 General Applications
    4. 8.4 Power Supply Recommendations
    5. 8.5 Layout
      1. 8.5.1 Layout Guidelines
      2. 8.5.2 Layout Examples
  10. Device and Documentation Support
    1. 9.1 接收文档更新通知
    2. 9.2 支持资源
    3. 9.3 Trademarks
    4. 9.4 静电放电警告
    5. 9.5 术语表
  11. 10Revision History
  12. 11Mechanical, Packaging, and Orderable Information

封装选项

请参考 PDF 数据表获取器件具体的封装图。

机械数据 (封装 | 引脚)
  • D|8
  • P|8
散热焊盘机械数据 (封装 | 引脚)
订购信息

Detailed Design Procedure

Determine the gain required by the inverting amplifier:

Equation 1. A V   =   V O U T V I N
Equation 2. A V   =   1.8 - 0.5   =   - 3.6

Once the desired gain is determined, choose a value for RI or RF. Choosing a value in the kΩ range is desirable because the amplifier circuit will use currents in the milliamp range. This causes the part will not draw too much current. This example will choose 10kΩ for RI which means 36kΩ will be used for RF. This was determined by Equation 3.

Equation 3. A V   =   -   R F R I